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There are better ways to generate a sequence of factorials #2

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AlexDaniel opened this issue Mar 10, 2018 · 1 comment
Open

There are better ways to generate a sequence of factorials #2

AlexDaniel opened this issue Mar 10, 2018 · 1 comment

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@AlexDaniel
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The document mentions $×=++$ for ^10, but that's not the shortest way:

say ($×=++$)xx⑩;
say [\*] 1…⑩;
@nwellnhof
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$×=++$ was mainly meant as a more complex example for anonymous state variables.

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@nwellnhof @AlexDaniel