Sorting the Odd way!.js

/*
Description:
Given an array of numbers, sort them in such a manner that all the odd numbers in the array are sorted in ascending order and the even numbers are sorted in descending order after the last odd number. For example [1,2,3,4,5,6,7,8,9] produces the output [1,3,5,7,9,8,6,4,2]. If the array contains decimals, round them down while checking for odd/even. The output must have the original numbers!

If there are no issues with the kata and you successfully completed it, please rank and upvote!
*/
function sortItOut(array){
  const odd=array.filter(v=>Math.floor(v)%2!==0).sort((a,b)=>a-b);
  const even=array.filter(v=>Math.floor(v)%2===0).sort((a,b)=>b-a);
  return odd.concat(even)
}