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Taking the example from Wikipedia, we can verify that for the matrix
i1 : A = matrix {{0,0,0,0,0,0,0},
{0,0,0,1,0,1,0},
{0,0,0,1,0,0,0},
{0,0,0,0,0,0,1},
{0,0,0,0,1,0,0},
{0,0,1,1,0,0,0},
{0,0,0,0,0,0,0},
{1,0,0,0,0,0,0}}
o1 = | 0 0 0 0 0 0 0 |
| 0 0 0 1 0 1 0 |
| 0 0 0 1 0 0 0 |
| 0 0 0 0 0 0 1 |
| 0 0 0 0 1 0 0 |
| 0 0 1 1 0 0 0 |
| 0 0 0 0 0 0 0 |
| 1 0 0 0 0 0 0 |
8 7
o1 : Matrix ZZ <-- ZZ
i2 : biword A
o2 = | 2 2 3 4 5 6 6 8 |
| 4 6 4 7 5 3 4 1 |
2 8
o2 : Matrix ZZ <-- ZZ
We also can verify the pair of semi-standard Young tableaux
i3 : (P, Q) = RSKCorrespondence A
o3 = (+---+---+---+, +---+---+---+)
| 1 | 4 | 4 | | 2 | 2 | 4 |
+---+---+---+ +---+---+---+
| 3 | 5 | | 3 | 5 |
+---+---+ +---+---+
| 4 | 7 | | 6 | 6 |
+---+---+ +---+---+
| 6 | | 8 |
+---+ +---+
o3 : Sequence
However, in the computation of the correspondence in the other direction (i.e., computing the image of $(P,Q)$), the biword of biword A
with the column order reversed. Below is the current reconstructed biword.
| 8 6 6 5 4 3 2 2 |
| 1 4 5 6 7 3 4 4 |
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