Implicit Call Expression

[HungMingWu]

I am not sure whether it is a bug.

class Packet;
	bit [3:0] command;
	integer status;

	function integer current_status();
		current_status = status;
	endfunction

	int incr = 0;

	function integer update_status();
		update_status = status;
		if (incr < 2) begin
			incr = incr + 1;
			update_status;
		end

		if (update_status == 0) 
			if (this.update_status)
				command[update_status] = 1'b0;
		return update_status;
	endfunction
endclass

In slang, it treat update_status as a variable symbol, so it prints expression is not allowed as a statement error.
But some commercial parser treat it as a call expression.
Like this

		if (incr < 2) begin
			incr = incr + 1;
			this.update_status;
		end

Any comment?

[MikePopoloski]

Yes, it does seem that all the commercial tools treat it as a function call. This seems like pretty terrible coding practice in my opinion but I will fix slang to behave the same way.