@@ -47,7 +47,7 @@ Among these are
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These and other applications prove the truth of the wise crack that
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``` {epigraph}
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- "in economics, a little knowledge of geometric series goes a long way "
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+ "In economics, a little knowledge of geometric series goes a long way. "
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```
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Below we'll use the following imports:
@@ -171,7 +171,7 @@ The right side records bank $i$'s liabilities,
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namely, the deposits $D_i$ held by its depositors; these are
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IOU's from the bank to its depositors in the form of either checking
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accounts or savings accounts (or before 1914, bank notes issued by a
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- bank stating promises to redeem note for gold or silver on demand).
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+ bank stating promises to redeem notes for gold or silver on demand).
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Each bank $i$ sets its reserves to satisfy the equation
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@@ -573,7 +573,7 @@ Recall that $R = 1+r$ and $G = 1+g$ and that $R > G$
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and $r > g$ and that $r$ and $g$ are typically small
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numbers, e.g., .05 or .03.
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- Use the Taylor series of $\frac{1}{1+r}$ about $r=0$,
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+ Use the [ Taylor series] ( https://en.wikipedia.org/wiki/Taylor_series ) of $\frac{1}{1+r}$ about $r=0$,
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namely,
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$$
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Expanding:
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$$
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- \begin{aligned} p_0 &=\frac{x_0(1-1+(T+1)^2 rg - r(T+1)+ g(T+1))}{1-1+r-g+rg} \\&=\frac{x_0(T+1)((T+1)rg+r-g)}{r-g+rg} \\ &\ approx \frac{x_0(T+1)(r-g)}{r-g}+\frac{x_0rg(T+1)}{r-g}\\ &= x_0(T+1) + \frac{x_0rg(T+1)}{r-g} \end{aligned}
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+ \begin{aligned} p_0 &=\frac{x_0(1-1+(T+1)^2 rg + r(T+1)- g(T+1))}{1-1+r-g+rg} \\&=\frac{x_0(T+1)((T+1)rg+r-g)}{r-g+rg} \\ &= \frac{x_0(T+1)(r-g)}{r-g + rg}+\frac{x_0rg(T+1)^2}{r-g+rg}\\ &\ approx \frac{x_0(T+1)(r-g)}{r-g}+\frac{x_0rg(T+1)}{r-g}\\ &= x_0(T+1) + \frac{x_0rg(T+1)}{r-g} \end{aligned}
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$$
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We could have also approximated by removing the second term
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