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constructBinaryTreeFromInorderAndPostorderTraversal.cpp
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constructBinaryTreeFromInorderAndPostorderTraversal.cpp
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// Source : https://oj.leetcode.com/problems/construct-binary-tree-from-inorder-and-postorder-traversal/
// Author : Hao Chen
// Date : 2014-07-10
/**********************************************************************************
*
* Given inorder and postorder traversal of a tree, construct the binary tree.
*
* Note:
* You may assume that duplicates do not exist in the tree.
*
*
**********************************************************************************/
#include <stdio.h>
#include <vector>
#include <queue>
using namespace std;
struct TreeNode {
int val;
TreeNode *left;
TreeNode *right;
TreeNode(int x) : val(x), left(NULL), right(NULL) {}
};
TreeNode *buildTree(vector<int> &inorder, int in_offset, vector<int> &postorder, int post_offset, int n );
TreeNode *buildTree(vector<int> &inorder, vector<int> &postorder) {
return buildTree(inorder, 0, postorder, 0, postorder.size());
}
// n - how many number, offset - start from where?
TreeNode *buildTree(vector<int> &inorder, int in_offset, vector<int> &postorder, int post_offset, int n ) {
if ( n<=0 || postorder.size()<=0 || inorder.size()<=0 ) return NULL;
TreeNode *root = new TreeNode(postorder[post_offset+n-1]);
if ( n==1 ){
return root;
}
//searching in inorder -- can be optimized by using <map>
int i;
for(i=in_offset; i<in_offset+n; i++){
if (inorder[i] == postorder[post_offset+n-1]){
break;
}
}
//error: not found
if (i == inorder.size()) return NULL;
int left_n = i - in_offset;
int right_n = in_offset + n - i - 1;
root->left = buildTree(inorder, in_offset, postorder, post_offset, left_n );
root->right = buildTree(inorder, i+1, postorder, post_offset+left_n, right_n);
return root;
}
//cause the problem: memory limited error
TreeNode *buildTree2(vector<int> &inorder, vector<int> &postorder) {
if (postorder.size()<=0 || inorder.size()<=0 ) return NULL;
int post_n = postorder.size();
TreeNode *root = new TreeNode(postorder[post_n-1]);
if ( inorder.size()==1 && postorder.size()==1 ){
return root;
}
//searching in inorder -- can be optimized by using <map>
int i;
for(i=0; i<inorder.size(); i++){
if (inorder[i] == postorder[post_n-1]){
break;
}
}
//error: not found
if (i == inorder.size()) return NULL;
vector<int> in(inorder.begin(), inorder.begin()+i);
vector<int> post(postorder.begin(), postorder.begin()+i);
if (in.size()>0) {
root->left = buildTree(in, post);
}
in.clear();
in.assign(inorder.begin()+i+1, inorder.end());
post.clear();
post.assign(postorder.begin()+i, postorder.end()-1);
if (in.size()>0) {
root->right = buildTree(in, post);
}
return root;
}
void printTree_pre_order(TreeNode *root)
{
if (root == NULL){
printf("# ");
return;
}
printf("%c ", root->val );
printTree_pre_order(root->left);
printTree_pre_order(root->right);
}
void printTree_in_order(TreeNode *root)
{
if (root == NULL){
printf("# ");
return;
}
printTree_in_order(root->left);
printf("%c ", root->val );
printTree_in_order(root->right);
}
void printTree_level_order(TreeNode *root)
{
queue<TreeNode*> q;
q.push(root);
while (q.size()>0){
TreeNode* n = q.front();
q.pop();
if (n==NULL){
printf("# ");
continue;
}
printf("%c ", n->val);
q.push(n->left);
q.push(n->right);
}
printf("\n");
}
int main()
{
int in_order[]={'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I'};
int post_order[]={'A', 'C', 'E', 'D', 'B', 'H', 'I', 'G', 'F'};
vector<int> inorder( in_order, in_order + 9 );
vector<int> postorder( post_order, post_order + 9 );
TreeNode* tree = buildTree(inorder, postorder);
printTree_level_order(tree);
printTree_pre_order(tree);
printf("\n");
printTree_in_order(tree);
printf("\n");
return 0;
}