Revert "Radix sort implementation in Python for issue #79" (#411)

Author: AshishOhri

.github/ISSUE_TEMPLATE/create-new-issue.md

@@ -0,0 +1,12 @@
+---
+name: Create new issue
+about: Describe this issue template's purpose here.
+title: ''
+labels: Hacktoberfest, Up-for-Grabs, good first issue, help wanted
+assignees: ''
+
+---
+
+* Please follow the [Contributing Guidelines](https://github.com/AshishOhri/Yet_Another_Algorithms_Repository/blob/master/CONTRIBUTING.md) & naming conventions in the guidelines accordingly. 🙂
+* Following naming guidelines is important to maintain consistency.😊
+* Please *NOTE*: In case, same implementation of an algorithm is submitted by someone else and it gets accepted, then your contribution won't be merged ( to avoid duplicates )

.github/PULL_REQUEST_TEMPLATE.md

@@ -0,0 +1,5 @@
+TICK ALL THE BOXES AFTER READING THEM (to tick them add tick inside the square brackets with no spaces like this [x])
+- [ ] I have read the <a href="https://github.com/yet-another-series/Yet_Another_Algorithms_Repository/blob/master/CONTRIBUTING.md">
+Contributing Guidelines</a> and naming conventions in the guidelines accordingly. 
+- [ ] I have checked that same implementation or the same code does not exist
+- [ ] I have referenced the issue (#issue_number) if the issue for the code exists

Algorithms/Divide_and _Conquer_Max_Min/python-Divide_and_conquer_MaxMin-O(n).py

@@ -0,0 +1,17 @@
+def max_min(li, left, right): 
+  global count 
+  if (left == right): 
+    return li[left],li[left]     
+  elif (right-left == 1): 
+    return max(li[left],li[right]), min(li[left],li[right]) 
+  else: 
+    mid = int((left + right) / 2)      
+    max1,min1 = max_min(li, left, mid)      	
+    max2,min2 = max_min(li, mid+1, right)     	
+    return max(max1,max2),min(min1,min2) 
+     
+li = [5,1,3,4,6,2] 
+maxi,mini = max_min(li, 0, len(li)-1) 
+print(maxi) 
+print(mini) 
+

Algorithms/binary_search/c-binary_search-O(log N).c

@@ -0,0 +1,48 @@
+#include <stdio.h>
+#define MAX 100005
+
+long long int arr[MAX];
+
+long long int binarySearch(long long int A[], long long int N, long long int ele) {
+    long long int beg, mid, end, flag = -1;
+    beg = 0;
+    end = N - 1;
+    while(beg <= end) {
+        mid = (beg + end) / 2;
+        if(A[mid] == ele) {
+            flag = mid;
+            break;
+        } else if(A[mid] < ele) {
+            beg = mid + 1;
+        } else {
+            end = mid - 1;
+        }
+    }
+    return flag;
+}
+
+int main() {
+    long long int N, S;
+    printf("\nEnter number of elements of array: ");
+    scanf("%lld", &N);
+    printf("\nEnter elements of array: ");
+    for(long long int i = 0 ; i < N ; i++) {
+        scanf("%lld", &arr[i]);
+    }
+    printf("\nEnter number of searches: ");
+    scanf("%lld", &S);
+    while(S) {
+        long long int T;
+        printf("\nEnter element to search for: ");
+        scanf("%lld", &T);
+        long long int f = -1;
+        f = binarySearch(arr, N, T);
+        if(f == -1) {
+            printf("%lld not found!", T);
+        } else {
+            printf("%lld found at index %lld", T, f);
+        }
+        S--;
+    }
+    return 0;
+}

Algorithms/binary_search/cpp-binary_search-O(log_n).cpp

@@ -0,0 +1,30 @@
+#include <bits/stdc++.h>
+
+using namespace std;
+
+int main()
+{
+	int l,n,t,h,flag=0,mid=0,s;
+	vector<int> a;
+	cin>>t;
+	while(t--)
+	{
+		cin>>s;
+		a.push_back(s);
+	}
+	cin>>n;
+	l=0;
+	h=a.size()-1;
+
+	while(l<h)
+	{
+		mid=(l+h)/2;
+		if(a[mid]>n) {h=mid-1;}
+		else if(a[mid]<n) {l=mid+1;}
+		else {flag=1; break;}
+	}
+	if(flag==1)
+        cout<<mid;
+
+	return 0;
+}

Algorithms/binary_search/java-binary_search-O(logN).java

@@ -0,0 +1,39 @@
+public class BinarySearch { 
+    // Returns index of x if it is present in arr[l.. 
+    // r], else return -1 
+    int binarySearch(int arr[], int l, int r, int x) { 
+        if (r>=l) { 
+            int mid = l + (r - l)/2; 
+   
+            // If the element is present at the  
+            // middle itself 
+            if (arr[mid] == x) 
+               return mid; 
+   
+            // If element is smaller than mid, then  
+            // it can only be present in left subarray 
+            if (arr[mid] > x) 
+               return binarySearch(arr, l, mid-1, x); 
+   
+            // Else the element can only be present 
+            // in right subarray 
+            return binarySearch(arr, mid+1, r, x); 
+        } 
+   
+        // We reach here when element is not present 
+        //  in array 
+        return -1; 
+    } 
+
+    public static void main(String args[]) { 
+        BinarySearch ob = new BinarySearch(); 
+        int arr[] = {2,3,4,10,40}; 
+        int n = arr.length; 
+        int x = 10; 
+        int result = ob.binarySearch(arr,0,n-1,x); 
+        if (result == -1) 
+            System.out.println("Element not present"); 
+        else
+            System.out.println("Element found at index " +  result); 
+    } 
+}

Algorithms/binary_search/js-binary_search-O(log-n).js

@@ -0,0 +1,43 @@
+// Sorted array
+const array = [1, 2, 3, 5, 7, 8, 9, 11, 14, 15, 16, 18];
+
+// Random value
+const value = Math.round(Math.random() * 20);
+
+console.log(`Searching ${value} in array [${array}]`);
+
+const binarySearch = (array, value, start, end) => {
+
+  // Base condition
+  if (start > end) {
+    return -1;
+  }
+
+  // Find the middle value
+  const middle = Math.floor((start + end) / 2);
+
+  // Compare with number
+  if (array[middle] === value) {
+    return middle;
+  }
+
+  // If element at middle is greater than value, search in the firts half of array
+  if (array[middle] > value) {
+    console.log(`Search in sub-array [${array.slice(start, middle - 1)}]`);
+    return binarySearch(array, value, start, middle - 1);
+  }
+  else {
+    // If element at midddle is smaller than value, search in the right half of array
+    console.log(`Search in sub-array [${array.slice(middle + 1, end)}]`);
+    return binarySearch(array, value, middle + 1, end);
+  }
+
+}
+
+const position = binarySearch(array, value, 0, array.length - 1);
+
+if (position >= 0) {
+  console.log(`${value} found at index ${position}`);
+} else {
+  console.log('Element not found');
+}

Algorithms/binary_search/python-binary_search-O(log(n)).py

@@ -0,0 +1,42 @@
+def binary_search(list_, val, asc=1):
+	'''
+	list_: sorted list with unique values
+	val: value to search
+	asc: asc==1 list is sorted in ascending order
+ 
+	Searches for a given element in a list sorted in ascending order. For searching in a list sorted in descending order, pass the argument value for asc as '0'.
+	'''
+	
+	lo = 0
+	hi = (len(list_)-1)
+	
+	while (lo <= hi):
+		mid = int(lo + (hi-lo)/2)
+		#print("mid", mid)
+		if (list_[mid] == val):
+			return mid
+		elif (list_[mid] > val):
+			if (asc == 1): # increasing
+				hi = mid-1
+			else :
+				lo = mid+1			
+		elif (list_[mid] < val):
+			if (asc == 1): # increasing
+				lo = mid+1
+			else :
+				hi = mid-1
+	return -1
+
+
+a = [14,15,16,17,18,19]
+a_= [19,18,17,16,15,14]
+
+print(binary_search(a, 16))
+print(binary_search(a, 19))
+print(binary_search(a, 18))
+print(binary_search(a, 11))
+
+print(binary_search(a_, 16, 0))
+print(binary_search(a_, 19, 0))
+print(binary_search(a_, 18, 0))
+print(binary_search(a_, 11, 0))

Algorithms/binary_search/python-binary_search-O(logn).py

@@ -0,0 +1,31 @@
+def binary_search(arr, l, r, x):
+	"""	Function to search number in a list in logn time"""
+	while l <= r:
+		mid = (l + r) // 2
+
+		# Check if x is present at mid
+		if arr[mid] == x:
+			return mid
+
+		# If x is greater, ignore left half
+		elif arr[mid] < x:
+			l = mid + 1
+
+		# If x is smaller, ignore right half
+		else:
+			r = mid - 1
+
+	# If we reach here, then the element
+	# was not present
+	return -1
+
+arr = list(map(int, input("Enter the sorted array: ").split()))
+x = int(input("Enter the number to search: "))
+
+# Function call
+result = binary_search(arr, 0, len(arr) - 1, x)
+
+if result != -1:
+	print("Element is present at position {}".format(result + 1))
+else:
+	print("Element is not present in array")

Algorithms/bubble_sort/c-bubble_sort-O(n^2).c

@@ -0,0 +1,42 @@
+#include <stdio.h>
+#define MAX 100005
+
+long long int arr[MAX];
+
+int bubbleSort(long long int A[], long long int N) {
+    int flag = 1;
+    for(long long int i = 0 ; i < N ; i++) {
+        if(A[i] > A[i + 1]) {
+            flag = 0;
+            long long int temp;
+            temp = A[i];
+            A[i] = A[i + 1];
+            A[i + 1] = temp;
+        }
+    }
+    return flag;
+}
+
+int main() {
+    long long int N;
+    int f = 0;
+    printf("\nEnter number of elements of array : ");
+    f = scanf("%lld", &N);
+    if(!f)
+        return -1;
+    printf("\nEnter elements of array : ");
+    for(long long int i = 0 ; i < N ; i++) {
+        f = scanf("%lld", &arr[i]);
+        if(!f)
+            return -1;
+    }
+    int sorted = 0;
+    while(!sorted) {
+        sorted = bubbleSort(arr, N - 1);
+    }
+    printf("\nSorted array : ");
+    for(long long int i = 0 ; i < N ; i++) {
+        printf("%lld ", arr[i]);
+    }
+    return 0;
+}

Algorithms/bubble_sort/cpp-bubble_sort-O(n^2).cpp

@@ -0,0 +1,42 @@
+// C++ program for implementation of Bubble sort 
+#include <bits/stdc++.h> 
+using namespace std; 
+
+void swap(int *xp, int *yp) 
+{ 
+	int temp = *xp; 
+	*xp = *yp; 
+	*yp = temp; 
+} 
+
+// A function to implement bubble sort 
+void bubbleSort(int arr[], int n) 
+{ 
+	int i, j; 
+	for (i = 0; i < n-1; i++)	 
+	
+	// Last i elements are already in place 
+	for (j = 0; j < n-i-1; j++) 
+		if (arr[j] > arr[j+1]) 
+			swap(&arr[j], &arr[j+1]); 
+} 
+
+/* Function to print an array */
+void printArray(int arr[], int size) 
+{ 
+	int i; 
+	for (i = 0; i < size; i++) 
+		cout << arr[i] << " "; 
+	cout << endl; 
+} 
+
+// Driver code 
+int main() 
+{ 
+	int arr[] = {64, 34, 25, 12, 22, 11, 90}; 
+	int n = sizeof(arr)/sizeof(arr[0]); 
+	bubbleSort(arr, n); 
+	cout<<"Sorted array: \n"; 
+	printArray(arr, n); 
+	return 0; 
+}