LSequence: Appending to Sequence apparently modifies the value?

[bajtix]

I was trying to create an LSequence with CanvasGroup alphas for a game. The following code, however, seems to cause all of the items to be visible at once for a single frame. This happens only sometimes and I was unable to isolate the issue, but it seems to happen only when adding motions to sequences in loops.

var lSequence = LSequence.Create();
lSequence.AppendInterval(m_defaultInterval);
lSequence.Append(LMotion.Create(1f, 0f, m_fadeDuration).BindToAlpha(m_groups[0]));

foreach (var w in m_groups.Skip(1)) {
    lSequence.Append(LMotion.Create(0f, 1f, m_fadeDuration).BindToAlpha(w));
    lSequence.AppendInterval(m_defaultInterval);
    lSequence.Append(LMotion.Create(1f, 0f, m_fadeDuration).BindToAlpha(w));
}
lSequence.Append(LMotion.Create(0f, 1f, m_fadeDuration).BindToAlpha(m_groups[0]));
lSequence.Run();

I was unable to capture this using screen recording software (it does not happen when recording for some reason), so here is a video of the issue I captured on my phone.

bug.mp4

[SwingWren]

Have the same issue I think.

This works as expected:

await LSequence.Create()
        .Append(LMotion.Create(origin, 100f, 0.3f).BindToLocalPositionX(rectTransform))
        .Run();

This adds a frame at the start of the sequence using the second animation position:

await LSequence.Create()
        .Append(LMotion.Create(origin, 100f, 0.3f).BindToLocalPositionX(rectTransform))
        .Append(LMotion.Create(100f, -100f, 1f).BindToLocalPositionX(rectTransform))
        .Run();

[legoritma]

This was also bugging with us. It happens because individual motion immediately bind start value on default (i think this behaviour should be disabled by sequence by default). You can solve via using .WithImmediateBind(false)

Example

await LSequence.Create()
        .Append(LMotion.Create(origin, 100f, 0.3f).BindToLocalPositionX(rectTransform))
        .Append(LMotion.Create(100f, -100f, 1f).WithImmediateBind(false).BindToLocalPositionX(rectTransform))
        .Run();