There are n
couples sitting in 2n
seats arranged in a row and want to hold hands.
The people and seats are represented by an integer array row
where row[i]
is the ID of the person sitting in the ith
seat. The couples are numbered in order, the first couple being (0, 1)
, the second couple being (2, 3)
, and so on with the last couple being (2n - 2, 2n - 1)
.
Return the minimum number of swaps so that every couple is sitting side by side. A swap consists of choosing any two people, then they stand up and switch seats.
Example 1:
Input: row = [0,2,1,3] Output: 1 Explanation: We only need to swap the second (row[1]) and third (row[2]) person.
Example 2:
Input: row = [3,2,0,1] Output: 0 Explanation: All couples are already seated side by side.
Constraints:
2n == row.length
2 <= n <= 30
n
is even.0 <= row[i] < 2n
- All the elements of
row
are unique.
[Greedy] [Depth-First Search] [Breadth-First Search] [Union Find] [Graph]
- First Missing Positive (Hard)
- Missing Number (Easy)
- K-Similar Strings (Hard)