using type declaration output as member function

[vinniefalco]

A nested "using" statement which declares a type is instead listed as a member function.
Example:

class params
{
public:
    /** A reference to an element.
    */
    /**@{*/
    struct reference
    {
    };
    using const_reference = reference;
    /**@}*/
};

Note how const_reference is in the Member Functions: