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You mentioned that xt = (1-t)x + ty, and in the code, t starts with eps (1e-3) in training, however, you used t=eps in inference and the input of model should be x_0 * (1-eps)+ y*eps accordingly. I feel quiet strange about this.
RectifiedFlow/ImageGeneration/losses.py
Line 101 in 9df93aa
You mentioned that xt = (1-t)x + ty, and in the code, t starts with eps (1e-3) in training, however, you used t=eps in inference and the input of model should be x_0 * (1-eps)+ y*eps accordingly. I feel quiet strange about this.
在采样的时候用的是xt = (1-t)x + ty, t的范围是[1e-3,1],训练的时候t=1e-3对应的是x_0 * (1-eps)+ y*eps,但是推理的时候t的起点也是1e-3,这时候是没有y用于计算x_t的,是出于什么原因这样设计的呢?
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