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AbsolutePermutation.cpp
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#include <bits/stdc++.h>
using namespace std;
string ltrim(const string &);
string rtrim(const string &);
vector<string> split(const string &);
/*
* Complete the 'absolutePermutation' function below.
*
* The function is expected to return an INTEGER_ARRAY.
* The function accepts following parameters:
* 1. INTEGER n
* 2. INTEGER k
*/
vector<int> absolutePermutation(int n, int k) {
// Case when k is 0, return the identity permutation
if (k == 0) {
vector<int> permutation(n);
iota(permutation.begin(), permutation.end(), 1);
return permutation;
}
// If n is not divisible by 2 * k, a valid permutation is not possible
if (n % (2 * k) != 0)
return {-1};
vector<int> permutation;
bool add = true;
// Iterate through numbers and alternate between adding and subtracting k
for (int i = 1; i <= n; ++i) {
if (add) {
permutation.push_back(i + k);
} else {
permutation.push_back(i - k);
}
// Flip `add` every k steps
if (i % k == 0) {
add = !add;
}
}
return permutation;
}
int main()
{
ofstream fout(getenv("OUTPUT_PATH"));
string t_temp;
getline(cin, t_temp);
int t = stoi(ltrim(rtrim(t_temp)));
for (int t_itr = 0; t_itr < t; t_itr++) {
string first_multiple_input_temp;
getline(cin, first_multiple_input_temp);
vector<string> first_multiple_input = split(rtrim(first_multiple_input_temp));
int n = stoi(first_multiple_input[0]);
int k = stoi(first_multiple_input[1]);
vector<int> result = absolutePermutation(n, k);
for (size_t i = 0; i < result.size(); i++) {
fout << result[i];
if (i != result.size() - 1) {
fout << " ";
}
}
fout << "\n";
}
fout.close();
return 0;
}
string ltrim(const string &str) {
string s(str);
s.erase(
s.begin(),
find_if(s.begin(), s.end(), not1(ptr_fun<int, int>(isspace)))
);
return s;
}
string rtrim(const string &str) {
string s(str);
s.erase(
find_if(s.rbegin(), s.rend(), not1(ptr_fun<int, int>(isspace))).base(),
s.end()
);
return s;
}
vector<string> split(const string &str) {
vector<string> tokens;
string::size_type start = 0;
string::size_type end = 0;
while ((end = str.find(" ", start)) != string::npos) {
tokens.push_back(str.substr(start, end - start));
start = end + 1;
}
tokens.push_back(str.substr(start));
return tokens;
}