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Description
For examples like the following, removing the semi-colon will make the example parse.
let y = 'a'.ToString();
do ()
The presence of ';'
prevents the scanner from inserting a dedent
token required to close the declaration expression.
Expected result:
let y = 'a'.ToString();
do ()
should parse the same as:
let y = 'a'.ToString()
do ()
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bugSomething isn't workingSomething isn't working