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lexicographically-smallest-string-after-reverse.cpp
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129 lines (120 loc) · 3.92 KB
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// Time: O(nlogn)
// Space: O(n)
// rolling hash, binary search
class Solution {
public:
string lexSmallest(string s) {
static const int64_t MOD = 1e9 + 7;
static const int64_t B = 29;
const int n = size(s);
const auto& binary_search = [](auto left, auto right, const auto& check) {
while (left <= right) {
const auto mid = left + (right - left) / 2;
if (check(mid)) {
right = mid - 1;
} else {
left = mid + 1;
}
}
return left;
};
vector<int64_t> prefix(n + 1);
for (int i = 0; i + 1 < size(prefix); ++i) {
prefix[i + 1] = (prefix[i] * B + s[i]) % MOD;
}
vector<int64_t> suffix(n + 1);
for (int i = size(suffix) - 2; i >= 0; --i) {
suffix[i] = (suffix[i + 1] * B + s[i]) % MOD;
}
vector<int64_t> base(n + 1, 1);
for (int i = 0; i + 1 < size(base); ++i) {
base[i + 1] = (base[i] * B) % MOD;
}
const auto& get_prefix_hash = [&](int l, int r) {
if (l > r) {
return static_cast<int64_t>(0);
}
return (prefix[r + 1] - prefix[l] * base[r - l + 1] % MOD + MOD) % MOD;
};
const auto& get_suffix_hash = [&](int l, int r) {
if (l > r) {
return static_cast<int64_t>(0);
}
return (suffix[l] - suffix[r + 1] * base[r - l + 1] % MOD + MOD) % MOD;
};
const auto& get_total_hash = [&](int k, int t, int l) {
if (!t) {
return l <= k
? get_suffix_hash(k - l, k - 1)
: ((get_suffix_hash(0, k - 1) * base[l - k]) % MOD + get_prefix_hash(k, l - 1)) % MOD;
}
const auto& nk = n - k;
return l <= nk
? get_prefix_hash(0, l - 1)
: ((get_prefix_hash(0, nk - 1) * base[l - nk]) % MOD + get_suffix_hash(n - (l - nk), n - 1)) % MOD;
};
const auto& get_char = [&](int k, int t, int idx) {
if (!t) {
return idx < k
? s[(k - 1) - idx]
: s[idx];
}
return idx < n - k
? s[idx]
: s[(n - 1) - (idx - (n - k))];
};
int best_k = 1, best_i = 0;
auto is_less = [&](int k, int i) {
const auto& idx = binary_search(0, n - 1, [&](int x) {
return get_total_hash(k, i, x + 1) != get_total_hash(best_k, best_i, x + 1);
});
return idx != n && get_char(k, i, idx) < get_char(best_k, best_i, idx);
};
const auto& mn = ranges::min(s);
for (int k = 1; k <= n; ++k) {
if (s[k - 1] != mn) {
continue;
}
if (is_less(k, 0)) {
best_k = k;
best_i = 0;
}
}
for (int k = 1; k <= n; ++k) {
if (!(s[size(s) - k] >= s.back())) {
continue;
}
if (is_less(k, 1)) {
best_k = k;
best_i = 1;
}
}
string result(s);
if (!best_i) {
reverse(begin(result), begin(result) + best_k);
} else {
reverse(begin(result) + (size(result) - best_k), end(result));
}
return result;
}
};
// Time: O(n^2)
// Space: O(1)
// brute force
class Solution2 {
public:
string lexSmallest(string s) {
string result = s;
for (int k = 2; k <= size(s); ++k) {
string t = s;
reverse(begin(t), begin(t) + k);
result = min(result, t);
}
for (int k = 2; k <= size(s); ++k) {
string t = s;
reverse(begin(t) + (size(t) - k), end(t));
result = min(result, t);
}
return result;
}
};