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No exit condition in bubblesort implementation #18

@dylanbeattie

Description

@dylanbeattie

Bubble-sort usually has a flag to indicate whether any elements were swapped during the last pass across the list - 'cos if no elements were swapped, the list is already in order and you can return. The implementation here doesn't have that, so if you bubble-sort a list that's already sorted, it still does O(n²) iterations.

The corrected implementation looks like this:

export const bubbleSort = function* (arr: number[]): SortingGenerator {
  for (let i = 0; i < arr.length; i++) {
	let sorted = true;
    for (let j = 0; j < arr.length - i - 1; j++) {
      yield { access: [j, j + 1], sound: j + 1 };
      if (arr[j] > arr[j + 1]) {
        sorted = false;
        const temp = arr[j];
        arr[j] = arr[j + 1];
        arr[j + 1] = temp;
      }
    }
	if (sorted) return;
  }
};

Would you be interested in a PR with a fix for this?

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