Given a string s
, return the number of palindromic substrings in it.
A string is a palindrome when it reads the same backward as forward.
A substring is a contiguous sequence of characters within the string.
Example 1:
Input: s = "abc" Output: 3 Explanation: Three palindromic strings: "a", "b", "c".
Example 2:
Input: s = "aaa" Output: 6 Explanation: Six palindromic strings: "a", "a", "a", "aa", "aa", "aaa".
Constraints:
1 <= s.length <= 1000
s
consists of lowercase English letters.
[String] [Dynamic Programming]
- Longest Palindromic Substring (Medium)
- Longest Palindromic Subsequence (Medium)
- Palindromic Substrings (Medium)
Hint 1
How can we reuse a previously computed palindrome to compute a larger palindrome?Hint 2
If “aba” is a palindrome, is “xabax” and palindrome? Similarly is “xabay” a palindrome?Hint 3
Complexity based hint:If we use brute-force and check whether for every start and end position a substring is a palindrome we have O(n^2) start - end pairs and O(n) palindromic checks. Can we reduce the time for palindromic checks to O(1) by reusing some previous computation?