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Only future parser does hash operators apparently #33
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Problem with this is that if you do $log_explicit_matches = $explicit_matches first, it creates a pointer to the same value, so all changes applied to the $log_* var will also be applied to the other one. Another problem is that if you do $var = something; $discard = inline_template('<% var = somestuff %>') the ruby code will create a new variable in its own scope, with or without @. |
alvagante
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Oct 6, 2013
Only future parser does hash operators apparently
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