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Homework 5
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Show that there exists an integer
$k$ , such that$k>10$ and$3k\equiv 2\pmod{5}$ and$k \mid 72$ . -
Let
$a$ be an integer for which$a\equiv 4\pmod{5}$ . Show that$a ^ 3 + 2a ^ 2 + 3\equiv 4\pmod{5}$ . -
Let
$x$ be an integer. Show that$x^5\equiv x\pmod{5}$ . -
Let
$a$ be a rational number, and suppose that for all rational numbers$b$ ,$a + b ^ 2$ is nonnegative. Show that$a$ is nonnnegative. -
Let
$n$ be a natural number, and suppose that every natural number$a$ between 6 and 10 inclusive is a divisor of$n$ . Show that every natural number$a$ between 1 and 5 inclusive is a divisor of$n$ .In the course of this problem, you may find yourself presented with some natural number (call it
$x$ ) for which you have lower and upper bounds (say$3 \le x$ and$x \le 6$ ). In such a situation you will want to do a case split:$x$ must be 3, 4, 5 or 6. The Lean tactic for this isinterval_cases
. (See Example 2.1.8 for an example usage.) -
Show that there exists a real number
$a$ , such that for all real numbers$b$ ,$a \le b^2$ . -
Show that for all sufficiently large real numbers
$x$ ,$x ^ 3 - 5x ≥ 11 x ^ 2$ . (Reminder, this means: there exists a real number$C$ , such that for all real numbers$x$ , if$x\geq C$ then$x ^ 3 - 5x ≥ 11 x ^ 2$ .)