Updated notebooks for Spring 2021.

jtkiley · Jan 18, 2021 · 6c29391 · 6c29391
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diff --git a/notebooks/0a_intro.ipynb b/notebooks/0a_intro.ipynb
diff --git a/notebooks/0b_anaconda.ipynb b/notebooks/0b_anaconda.ipynb
diff --git a/notebooks/1a_python1.ipynb b/notebooks/1a_python1.ipynb
@@ -512,7 +512,7 @@
      "name": "stdout",
      "output_type": "stream",
      "text": [
-      "2020-01-12 15:08:41.567360\n"
+      "2021-01-18 17:31:51.092606\n"
      ]
     }
    ],
@@ -530,9 +530,9 @@
      "name": "stdout",
      "output_type": "stream",
      "text": [
-      "2020\n",
+      "2021\n",
       "1\n",
-      "12\n"
+      "18\n"
      ]
     }
    ],
@@ -552,7 +552,7 @@
      "name": "stdout",
      "output_type": "stream",
      "text": [
-      "2019-01-12 15:08:41.567360\n"
+      "2020-01-19 17:31:51.092606\n"
      ]
     }
    ],
@@ -831,7 +831,130 @@
    "cell_type": "markdown",
    "metadata": {},
    "source": [
-    "## Bonus topics\n",
+    "# Breakout Exercises\n",
+    "\n",
+    "Let's do a few exercises to reinforce the concepts we learned above.\n",
+    "\n",
+    "\n",
+    "1. ints and floats\n",
+    "1. strings\n",
+    "1. dictionaries"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## EX1: ints and floats\n",
+    "\n",
+    "This is fairly strightforward, so let's calculate two things.\n",
+    "\n",
+    "1. Subtract the number of doctoral students in your breakout room from the total number of participants.\n",
+    "1. Compute the proportion of doctoral students to total participants in your breakout room."
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 35,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "# 1-1 code\n"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 36,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "# 1-2 code\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## EX2: strings\n",
+    "\n",
+    "1. Create a string containing `Hello, World!` and assign it to the name `z_string`.\n",
+    "1. Take `z_string` and add (using `+`) the string ` I'm [yourname].` to it (filling in your name).\n",
+    "1. Display the original string, verifying that the last step didn't change it."
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 37,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "# 2-1 code\n"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 38,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "# 2-2 code\n"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 39,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "# 2-3 code\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## EX3: dictionaries\n",
+    "\n",
+    "Dictionaries are usefful for a number of things, including as a lightweight way to represent a row of data.\n",
+    "When we use them this way, the keys are like column names, and the values are like the actual data.\n",
+    "\n",
+    "1. Assign `z_dict` to a dictionary with the key `'name'` and a value of the name of the breakout room member who is screen sharing.\n",
+    "1. Update the dictionary with another key `'affil'` and a value of the affiliation of the breakout room member who is screen sharing.\n",
+    "1. Use the indexing syntax to retrieve the value corresponding with the key `'affil'`."
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 40,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "# 3-1 code\n"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 41,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "# 3-2 code\n"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 42,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "# 3-3 code\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Bonus topics\n",
     "\n",
     "We won't cover these directly, but here are two other topics that are good to know.\n",
     "\n",
@@ -858,7 +981,7 @@
    "name": "python",
    "nbconvert_exporter": "python",
    "pygments_lexer": "ipython3",
-   "version": "3.7.6"
+   "version": "3.8.5"
   }
  },
  "nbformat": 4,

diff --git a/notebooks/1b_python2.ipynb b/notebooks/1b_python2.ipynb
@@ -951,6 +951,92 @@
     "1. Finally, it resets the index column and drops the old index values."
    ]
   },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Breakout Exercises\n",
+    "\n",
+    "Let's do two exercises to reinforce the concepts we learned above.\n",
+    "\n",
+    "\n",
+    "1. functions\n",
+    "1. loops"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## EX1: functions\n",
+    "\n",
+    "Let's make a function to do the temperature calculation in the other direction.\n",
+    "\n",
+    "1. Create a function named `c_to_f()` that takes a temerature in celsius and returns the temperature in fahrenheit. You may need to google the formula (I did).\n",
+    "1. Try your function by converting `100` from C to F."
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 42,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "# 1-1 code\n"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 43,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "# 1-2 code\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## EX2: loops\n",
+    "\n",
+    "Loops let us take a procedure and repeat it.\n",
+    "We'll use a `for` loop here to apply a simple computation.\n",
+    "\n",
+    "1. Create a list, named `x_list`, that contains the integers `1` through `5`.\n",
+    "1. Create a new list, named `y_list` where each element is `2` times the corresponding element in `x_list`. Use a `for` loop.\n",
+    "1. Create a new list, named `z_list`, that matches what you did for `y_list`, but use a list comprehension to construct it.\n",
+    "\n",
+    "**Note:** This is the first exercise where some cells will have multiple lines of code, but that will be the norm going forward."
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 44,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "# 2-1 code\n"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 45,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "# 2-2 code\n"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 46,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "# 2-3 code\n"
+   ]
+  },
   {
    "cell_type": "markdown",
    "metadata": {},
@@ -970,7 +1056,7 @@
   },
   {
    "cell_type": "code",
-   "execution_count": 42,
+   "execution_count": 47,
    "metadata": {},
    "outputs": [],
    "source": [
@@ -979,7 +1065,7 @@
   },
   {
    "cell_type": "code",
-   "execution_count": 43,
+   "execution_count": 48,
    "metadata": {},
    "outputs": [
     {
@@ -988,7 +1074,7 @@
        "array([ 0.        , 22.22222222, 47.22222222])"
       ]
      },
-     "execution_count": 43,
+     "execution_count": 48,
      "metadata": {},
      "output_type": "execute_result"
     }
@@ -999,7 +1085,7 @@
   },
   {
    "cell_type": "code",
-   "execution_count": 44,
+   "execution_count": 49,
    "metadata": {},
    "outputs": [
     {
@@ -1169,7 +1255,7 @@
        " 'view']"
       ]
      },
-     "execution_count": 44,
+     "execution_count": 49,
      "metadata": {},
      "output_type": "execute_result"
     }
@@ -1195,7 +1281,7 @@
    "name": "python",
    "nbconvert_exporter": "python",
    "pygments_lexer": "ipython3",
-   "version": "3.7.6"
+   "version": "3.8.5"
   }
  },
  "nbformat": 4,