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CODECOV-AI DEMO: Add get_subscription_plan(type) #847

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@ndmanvar ndmanvar commented Jun 6, 2025

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@ndmanvar ndmanvar requested a review from a team as a code owner June 6, 2025 20:55
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codecov bot commented Jun 6, 2025

Codecov Report

Attention: Patch coverage is 50.00000% with 1 line in your changes missing coverage. Please review.

Project coverage is 27.90%. Comparing base (526a3ce) to head (617f8f2).

✅ All tests successful. No failed tests found.

Files with missing lines Patch % Lines
flask/src/utils.py 50.00% 1 Missing ⚠️
Additional details and impacted files
@@            Coverage Diff             @@
##           master     #847      +/-   ##
==========================================
+ Coverage   27.86%   27.90%   +0.04%     
==========================================
  Files          41       41              
  Lines        1055     1057       +2     
  Branches      115      115              
==========================================
+ Hits          294      295       +1     
- Misses        742      743       +1     
  Partials       19       19              
Flag Coverage Δ
api 6.82% <50.00%> (+0.18%) ⬆️
frontend 44.72% <ø> (ø)
Components Coverage Δ
checkout_module 6.82% <50.00%> (+0.18%) ⬆️
product_component 41.47% <ø> (ø)
Files with missing lines Coverage Δ
flask/src/utils.py 60.37% <50.00%> (-0.41%) ⬇️

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ndmanvar commented Jun 6, 2025

@codecov-ai-reviewer review

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codecov-ai bot commented Jun 6, 2025

On it! We are reviewing the PR and will provide feedback shortly.

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codecov-ai bot commented Jun 6, 2025

PR Description

This pull request introduces a utility function, get_subscription_plan, to determine the subscription plan type based on a given input. The function aims to simplify the logic for retrieving the subscription plan, defaulting to 'annual' if the input is not 'monthly'.

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Key Technical Changes

A new function get_subscription_plan(type) is added to utils.py. This function takes a string type as input and returns 'monthly' if the input is 'monthly', otherwise it returns 'annual'. The implementation uses a simple conditional expression.

Architecture Decisions

The decision to add this function to utils.py suggests it's intended to be a general-purpose utility function accessible from various parts of the application. The function's simple logic doesn't introduce any complex architectural patterns.

Dependencies and Interactions

This function doesn't have any direct dependencies on other modules. It's expected to be used by other parts of the application that need to determine the subscription plan type, such as user account management or billing modules.

Risk Considerations

The function currently lacks input validation. If the input type is not explicitly 'monthly', it defaults to 'annual'. This might lead to unexpected behavior if the input is intended to represent a different plan type or an invalid value. Additionally, the lack of type hints reduces code clarity and maintainability. The absence of unit tests means the function's behavior is not automatically verified.

Notable Implementation Details

The function uses a ternary operator for conciseness. Reviewers should pay attention to the lack of input validation and consider adding more robust error handling or input sanitization to prevent unexpected behavior.

Comment on lines +74 to +75

def get_subscription_plan(type):
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The parameter name type shadows the built-in Python function type(). It's recommended to avoid using Python keywords or built-in function names as variable names. Consider using a more descriptive name like plan_type or subscription_type.

Suggested change
def get_subscription_plan(type):
def get_subscription_plan(plan_type):
return 'monthly' if plan_type == 'monthly' else 'annual'

Comment on lines +74 to +75

def get_subscription_plan(type):
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The function lacks a docstring that explains its purpose, parameters, and return values. Adding proper documentation improves code maintainability and helps other developers understand the function's purpose.

Suggested change
def get_subscription_plan(type):
def get_subscription_plan(plan_type):
"""Return the subscription plan type based on the input.
Args:
plan_type (str): The type of subscription ('monthly' or any other value)
Returns:
str: 'monthly' if plan_type is 'monthly', otherwise 'annual'
"""
return 'monthly' if plan_type == 'monthly' else 'annual'

Comment on lines +74 to +75

def get_subscription_plan(type):
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The function lacks type annotations which would improve code clarity and enable better IDE support and static type checking.

Suggested change
def get_subscription_plan(type):
def get_subscription_plan(plan_type: str) -> str:
"""Return the subscription plan type based on the input.
Args:
plan_type (str): The type of subscription ('monthly' or any other value)
Returns:
str: 'monthly' if plan_type is 'monthly', otherwise 'annual'
"""
return 'monthly' if plan_type == 'monthly' else 'annual'

Comment on lines +74 to +75

def get_subscription_plan(type):
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The function assumes only two plan types (monthly and annual) and doesn't handle invalid input. Consider adding validation or being more explicit about the default case.

Suggested change
def get_subscription_plan(type):
def get_subscription_plan(plan_type: str) -> str:
"""Return the subscription plan type based on the input.
Args:
plan_type (str): The type of subscription ('monthly' or 'annual')
Returns:
str: 'monthly' if plan_type is 'monthly', otherwise 'annual'
Raises:
ValueError: If plan_type is not 'monthly' or 'annual'
"""
if plan_type == 'monthly':
return 'monthly'
elif plan_type == 'annual':
return 'annual'
else:
raise ValueError(f"Invalid subscription plan type: {plan_type}. Expected 'monthly' or 'annual'.")

Comment on lines +74 to +75

def get_subscription_plan(type):
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Consider adding unit tests for this new utility function to ensure it behaves as expected in all scenarios.

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ndmanvar commented Jun 6, 2025

@codecov-ai-reviewer test

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codecov-ai bot commented Jun 6, 2025

On it! Codecov is generating unit tests for this PR.

@codecov-ai codecov-ai bot mentioned this pull request Jun 6, 2025
@ndmanvar ndmanvar changed the title Add get_subscription_plan(type) CODECOV-AI DEMO: Add get_subscription_plan(type) Jun 6, 2025
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