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CODECOV-AI DEMO: Add get_subscription_plan(type)
#847
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Codecov ReportAttention: Patch coverage is
✅ All tests successful. No failed tests found.
Additional details and impacted files@@ Coverage Diff @@
## master #847 +/- ##
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+ Coverage 27.86% 27.90% +0.04%
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Files 41 41
Lines 1055 1057 +2
Branches 115 115
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+ Hits 294 295 +1
- Misses 742 743 +1
Partials 19 19
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@codecov-ai-reviewer review |
On it! We are reviewing the PR and will provide feedback shortly. |
PR DescriptionThis pull request introduces a utility function, Click to see moreKey Technical ChangesA new function Architecture DecisionsThe decision to add this function to Dependencies and InteractionsThis function doesn't have any direct dependencies on other modules. It's expected to be used by other parts of the application that need to determine the subscription plan type, such as user account management or billing modules. Risk ConsiderationsThe function currently lacks input validation. If the input Notable Implementation DetailsThe function uses a ternary operator for conciseness. Reviewers should pay attention to the lack of input validation and consider adding more robust error handling or input sanitization to prevent unexpected behavior. |
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def get_subscription_plan(type): |
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The parameter name type
shadows the built-in Python function type()
. It's recommended to avoid using Python keywords or built-in function names as variable names. Consider using a more descriptive name like plan_type
or subscription_type
.
def get_subscription_plan(type): | |
def get_subscription_plan(plan_type): | |
return 'monthly' if plan_type == 'monthly' else 'annual' |
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def get_subscription_plan(type): |
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The function lacks a docstring that explains its purpose, parameters, and return values. Adding proper documentation improves code maintainability and helps other developers understand the function's purpose.
def get_subscription_plan(type): | |
def get_subscription_plan(plan_type): | |
"""Return the subscription plan type based on the input. | |
Args: | |
plan_type (str): The type of subscription ('monthly' or any other value) | |
Returns: | |
str: 'monthly' if plan_type is 'monthly', otherwise 'annual' | |
""" | |
return 'monthly' if plan_type == 'monthly' else 'annual' |
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def get_subscription_plan(type): |
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The function lacks type annotations which would improve code clarity and enable better IDE support and static type checking.
def get_subscription_plan(type): | |
def get_subscription_plan(plan_type: str) -> str: | |
"""Return the subscription plan type based on the input. | |
Args: | |
plan_type (str): The type of subscription ('monthly' or any other value) | |
Returns: | |
str: 'monthly' if plan_type is 'monthly', otherwise 'annual' | |
""" | |
return 'monthly' if plan_type == 'monthly' else 'annual' |
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def get_subscription_plan(type): |
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The function assumes only two plan types (monthly and annual) and doesn't handle invalid input. Consider adding validation or being more explicit about the default case.
def get_subscription_plan(type): | |
def get_subscription_plan(plan_type: str) -> str: | |
"""Return the subscription plan type based on the input. | |
Args: | |
plan_type (str): The type of subscription ('monthly' or 'annual') | |
Returns: | |
str: 'monthly' if plan_type is 'monthly', otherwise 'annual' | |
Raises: | |
ValueError: If plan_type is not 'monthly' or 'annual' | |
""" | |
if plan_type == 'monthly': | |
return 'monthly' | |
elif plan_type == 'annual': | |
return 'annual' | |
else: | |
raise ValueError(f"Invalid subscription plan type: {plan_type}. Expected 'monthly' or 'annual'.") |
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def get_subscription_plan(type): |
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Consider adding unit tests for this new utility function to ensure it behaves as expected in all scenarios.
@codecov-ai-reviewer test |
On it! Codecov is generating unit tests for this PR. |
get_subscription_plan(type)
get_subscription_plan(type)
No description provided.